(3/y-2)+(2y/4-y^2)=(5/y+2)

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Solution for (3/y-2)+(2y/4-y^2)=(5/y+2) equation: 



(3/y-2)+(2y/4-y^2)=(5/y+2)

We move all terms to the left:

(3/y-2)+(2y/4-y^2)-((5/y+2))=0



Domain of the equation: 4-y^2)!=0

We move all terms containing y to the left, all other terms to the right

-y^2)!=-4

y!=-4/1

y!=-4

y∈R





Domain of the equation: y-2)!=0

y∈R





Domain of the equation: y+2))!=0

y∈R



We get rid of parentheses

-y^2+2y/4+3/y-((5/y+2))-2=0

We calculate fractions

We do not support eypression: y^3

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